In
this article formulation(reconstruction) of the problem has been shown
for solving Linear Programming Problem using the Simplex Method for Minimizing Objective Function with the help of some examples with mix constraints type.
Example
Consider the problem,
Minimize Z= 3x1 + 8x2
Subject to,
x1 + x2 = 200
x1 <= 80
x2 >= 60
x1, x2 >=0
After converting all the in-equations as equations by introducing the slack and suplus variables we can rewrite the problem as,
Minimize Z= 3x1 + 8x2 + 0.s1 + 0.s2 + M.A1 + M.A2
Subject to,
x1 + x2 + A1 = 200
Note That, the following steps may be followed to solve the LP problem:
Subject to,
x1 + x2 + A1 = 200
x1 + s1 = 80
x2 - s2 + A2 = 60
x1, x2 >=0
The initial solution can be obtained by assuming,
x1= x2= s2= 0
So,
A1= 200
s1= 80
A2= 60
Note That, the following steps may be followed to solve the LP problem:
- Create the initial table
- Find Zj using the formula ⅀(CBi*aij)
- Find Cj - Zj
- If all the values in Cj - Zj are >= 0, then, there are no chance of further improvement in the minimization. So, Stop else, proceed to next step.
- Select the Smallest Value among all (Cj - Zj) which are -ve to find the Key column(Xi) and entering variable.
- Find the minimum ration among all XB/Xi, to identify the key row & departing variable. Ignore if there are any -ve value in min ration column.
- The intersection of key row & key column is the key element(pivot).
- Place entering variable(Xi) by replacing Departing variable.
- Put the Cj value corresponding to Xi under CB of newly entered variable Xi.
- Multiply the Key row by (1/key element) to make the pivot(key element) 1.
- For each remaining row i perform Rowi = Rowi - Key Row*aik, where Xk is the key column.
- Again start computation from step 2.
Done Sir .
ReplyDeleteDone sir
ReplyDeleteDone sir
ReplyDeleteDone Sir
ReplyDeleteDone sir
ReplyDeleteDone sir.
ReplyDeleteDone Sir
ReplyDeleteSir, I think,
ReplyDeleteIn Note - 4, there will be "Minimisation" instead of "Maximisation".
Yes.
DeleteThank you....
4. If all the values in Cj - Zj are >= 0, then, there are no chance of further improvement in the maximization.
ReplyDeleteSir, in the above step, will it be maximization or minimization?
Yes.
DeleteThank you....
Sir s1 is added in the 2nd constraint(in a minization problem,where generally surplus variable is written with a -ve sign), because the sign is <=.Is my notion right?
ReplyDeleteLet try this answer from Others....
DeleteGenerally for minimization problem type of constraints is >=. So, the in-equations are converted to equations by subtracting Surplus variables.
DeleteS1 is slack Variable.
Deletes1 is slack variable
Deletes2 is surplus variable
Deletes2 is Surplus variable.
DeleteS2 is surplus variable
DeleteS2 is surplus variable, because it is getting subtracted.
DeleteYes sir..thank you everyone.
DeleteSolve:
ReplyDelete"Realization" - "Reading" = ?
Did not get the answer yet....
DeleteSir, can't understand.
DeleteYes sir I get the answer
Deletecan't understand sir.
Delete"Realization" - "Reading" = "Understanding".
DeleteThink a little about the process
DeleteRead and
Realize....
What they requires?....
This -(minus) indicates "Set Difference" not "Arithmetic Subtraction"....
Reading Means Something Understand & Read After Realization Means Completely Understand..
DeleteReading requires only to work by eye....
DeleteRealization requires Reading + EFFORT (for "analysis", "calculate", "compare" etc) to understand....
Got It Sir
DeleteAttendance submitted sir.
ReplyDeleteDone sir
ReplyDeleteDone Sir
ReplyDeleteDone Sir
ReplyDeleteDone sir
ReplyDeleteDone sir
ReplyDeleteAttendance Submitted.
ReplyDelete